Skip to main content
4 events
when toggle format what by license comment
Oct 3, 2023 at 18:03 comment added mmesser314 I take it back. You did. But you are not getting the same expression as in the post. I see it. $I_D = 1/2mr^2$
Oct 3, 2023 at 15:27 comment added Eli @mmeser $~I_D~$ appear at the denominator of $~ω^2~$ ?
Oct 3, 2023 at 13:56 comment added mmesser314 You might check your calculation. You didn't add $I_D$ to the expression for $\omega^2$.
Oct 2, 2023 at 15:55 history answered Eli CC BY-SA 4.0