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Sep 18, 2023 at 17:40 history edited John CC BY-SA 4.0
added 240 characters in body
Sep 18, 2023 at 17:38 comment added John @ShKol I agree. Thanks for pointing that out.
Sep 18, 2023 at 15:36 comment added ShKol This was not done in the answer you mention - that integral is over the momentum and the position derivative brings down the momentum from the exponential. This is not the same as using the position space representation of the momentum (which would, of course, lead to the commutator mentioned by the OP).
Sep 18, 2023 at 15:20 history answered John CC BY-SA 4.0