It is given that $\frac{ds}{dt} = \frac{d\theta}{dt}$, i.e. the time derivative of s and $\theta$ are equal to each other.

Does it follow that for small values of $t$, $\Delta s ≈ \Delta \theta$?

It is given that $\frac{ds}{dt} = \frac{d\theta}{dt}$, i.e. the time derivative of s and $\theta$ are equal to each other.

Does it follow that for small values of $t$, $\Delta s ≈ \Delta \theta$? My thought process for this was that if I multiply $dt$ on both sides, I am left with just the value of $ds=d\theta$, which I can rewrite as $\Delta s ≈ \Delta \theta$. Would I be correct in thinking this?