Timeline for Is the Boltzmann distribution 'memoryless'? What is the physical interpretation?
Current License: CC BY-SA 4.0
13 events
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| Sep 18, 2023 at 18:31 | vote | accept | bananenheld | ||
| Sep 18, 2023 at 12:52 | history | edited | Quillo | CC BY-SA 4.0 |
typo correction and link to the exact meaning of "memoryless" for the exponential distribution
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| Sep 18, 2023 at 7:03 | comment | added | Quillo | I think I understood the question. The OP is asking about the memoryless property of the exponential distribution in the context of time series (i.e. Poisson point process). Since the Gibbs weight contains an exponential, the OP is assuming that it should have this property as well (how and for what it's unclear, because in this case we are not in the context of time series). I edited the question accordingly. | |
| Sep 18, 2023 at 7:02 | history | edited | Quillo | CC BY-SA 4.0 |
Added links to provide context and clarify the question
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| Sep 17, 2023 at 19:13 | comment | added | John Doty | What's your experiment? For some experiments, you'll see correlations between successive measurements, for others you won't. The "memoryless" concept isn't insightful here. | |
| Sep 17, 2023 at 19:08 | comment | added | bananenheld | I adjusted it, thank you for your comment | |
| Sep 17, 2023 at 19:06 | history | edited | bananenheld | CC BY-SA 4.0 |
deleted 27 characters in body
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| Sep 16, 2023 at 18:24 | comment | added | hft | "Could somehow help me?" is not a clear question. Consider rewriting your question more clearly. | |
| Sep 16, 2023 at 17:59 | comment | added | Quillo | "It is known by being 'memoryless'." -> please provide a reference for this concept ad clarify its meaning. What do you mean by "memoryless"? (My guess: it is a measure for an equilibrium system under certain constraints and equilibrium systems are the ones that mostly "forget" about their initial condition.) Maybe this helps: physics.stackexchange.com/a/389714/226902 | |
| Sep 16, 2023 at 17:17 | history | edited | bananenheld | CC BY-SA 4.0 |
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| Sep 10, 2023 at 16:06 | answer | added | GiorgioP-DoomsdayClockIsAt-90 | timeline score: 4 | |
| Sep 10, 2023 at 14:27 | comment | added | Zarathustra | You are mixing the concept of dynamics of the system (i.e. evolution from one state A at some time t to another state B at a later time t') with that of equilibrium, where essentially the concept of time is absent. In equilibrium, you can only assume that all microstates accessible correspond to a given probability distribution. In your case, because you are fixing the temperature of the system, this gives the Boltzmann distribution. However, if instead you would have fixed the energy, your distribution would be the constant distribution, meaning each state is equally likely. | |
| Sep 10, 2023 at 13:48 | history | asked | bananenheld | CC BY-SA 4.0 |