Timeline for Spontaneous Parametric Down Conversion (SPDC): why the asymmetric Bell state?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 5, 2023 at 0:42 | answer | added | benrg | timeline score: 1 | |
| Sep 4, 2023 at 22:54 | comment | added | ZeroTheHero | see Bartlett, S. D., et al. "Unitary transformations for testing Bell inequalities." Physical Review A 63.4 (2001): 042310 available here | |
| Sep 4, 2023 at 22:45 | answer | added | DrChinese | timeline score: 2 | |
| Sep 2, 2023 at 4:06 | answer | added | flippiefanus | timeline score: 2 | |
| Sep 1, 2023 at 14:27 | comment | added | DrChinese | The asymmetric Bell state you mention is common to Type II PDC crystals. Another technique is used that produces the symmetric state HH+VV. It is called Type I PDC, and uses 2 crystals that are oriented 90 degrees apart. This excellent reference explains it: arxiv.org/abs/quant-ph/0205171 | |
| Sep 1, 2023 at 14:19 | history | edited | garyp | CC BY-SA 4.0 |
added 3 characters in body
|
| Sep 1, 2023 at 14:19 | comment | added | garyp | @flippiefanus Thanks. A case of typing without thinking. Corrected. | |
| Sep 1, 2023 at 2:56 | comment | added | flippiefanus | Please define your notation. There seems to be four polarizations in each term, while there is only supposed to be two photons. | |
| Sep 1, 2023 at 1:26 | history | asked | garyp | CC BY-SA 4.0 |