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Jul 24, 2023 at 19:08 vote accept gnyszbr21
Jul 24, 2023 at 10:41 history became hot network question
Jul 24, 2023 at 6:16 history edited Qmechanic
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S Jul 24, 2023 at 4:38 history suggested Golden_Hawk CC BY-SA 4.0
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Jul 24, 2023 at 4:15 review Suggested edits
S Jul 24, 2023 at 4:38
Jul 24, 2023 at 3:13 comment added gnyszbr21 @naturallyInconsistent I meant that in km/s but yeah guess I forgot the units. Thank you for your answer.
Jul 24, 2023 at 3:00 answer added Dale timeline score: 7
Jul 24, 2023 at 2:56 comment added PM 2Ring The local speed of light is always c for any observer, but see en.wikipedia.org/wiki/Shapiro_time_delay
Jul 24, 2023 at 2:53 comment added naturallyInconsistent The value of $c$ is $3\times10^8\,$m/s so $c^2=9\times10^{16}\,$(m/s)$^2$ i.e. you are missing 6 orders of magnitude or something. But it really does not matter. The actual thing that matters is that if you wish to understand the Special Theory of Relativity, you should be measuring time in light-metres, and if you do so, then all 4 measurements are using the same units, and it no longer makes sense to ask what happens if different regions of spacetime have different speeds of light. Even if it is different, no experiment can tell that they are different.
S Jul 24, 2023 at 2:41 review First questions
Jul 24, 2023 at 4:15
S Jul 24, 2023 at 2:41 history asked gnyszbr21 CC BY-SA 4.0