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Jul 22, 2023 at 15:06 comment added Lenard Kasselmann Yes, this makes perfect sense to me now. It's just very unusual that an expression can be brought into a more convenient form by including higher-order terms. Usually it's the other way around :D
Jul 22, 2023 at 14:31 comment added Ghorbalchov Also note for example that the Taylor expansion of $\frac{1}{x-a}$ is just $\frac{1}{x}+\frac{1}{x}a\frac{1}{x}$ to first order. So the effect of adding on all the other higher order terms in a geometric series is just for illustrative purposes and they don't actually do anything to the result.
Jul 22, 2023 at 14:24 comment added Ghorbalchov Yes, that sounds right to me
Jul 22, 2023 at 14:21 comment added Lenard Kasselmann Thanks a lot! So in other words: If we only consider the first order, we can add and subtract higher-order contributions as we like, because by design, these won't change the first-order result.
Jul 22, 2023 at 14:19 comment added Ghorbalchov I have now corrected the original question as well to be in line with this answer.
Jul 22, 2023 at 14:17 vote accept Lenard Kasselmann
Jul 22, 2023 at 14:12 history answered Ghorbalchov CC BY-SA 4.0