Timeline for Understanding the potential step for a particle in 1D
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Jul 19, 2023 at 8:13 | vote | accept | Rasmus Andersen | ||
| Jul 19, 2023 at 8:13 | comment | added | Rasmus Andersen | Okay, thank you. This clears up some of the confusion, but I will sit down and study the details at a later point. | |
| Jul 18, 2023 at 11:14 | comment | added | Roger V. | @RasmusAndersen see also the remark that I added to the answer. | |
| Jul 18, 2023 at 11:14 | history | edited | Roger V. | CC BY-SA 4.0 |
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| Jul 18, 2023 at 10:59 | comment | added | Roger V. | @RasmusAndersen term $Fe^{iqx}$ corresponds to the current flowing to the right, whereas term $G^{-iqx}$ is the current flowing to the left - you can easily calculate the current for a plane wave using usual prescription. The solution in the OP is for the (incoming) wave incident from the left. If you consider a wave incident from the right or if you decide to work with outgoing waves, you will have $G^{-iqx}$. | |
| Jul 18, 2023 at 10:25 | comment | added | Rasmus Andersen | Okay, thank you for the good links you provided. I understand that we can determine the two solutions to TISE by for instance considering the wave flux propagating from left-to-right (in this problem specifically). Now, if we do consider this derivation-method for the two solutions, I still cannot see how the term $G\text{e}^{-iqx}$ is discarded. Although the links you provided give good insight, I am not quite sure how they answer this question in particular. | |
| Jul 18, 2023 at 9:55 | history | answered | Roger V. | CC BY-SA 4.0 |