Timeline for Why do these two ways to calculate the resistance at a given temperature give different answers?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Sep 14, 2013 at 5:49 | vote | accept | user80551 | ||
| Sep 13, 2013 at 17:53 | comment | added | jdj081 | Yes. Sorry, I had a typo. I edited to fix it. It should have read "a slope of 0.005 /∘C" which is 0.5 (or 50%) per 100C. And with a reference of 100 Ohms 50% = 50 Ohms. The answer is the same 50 Ohms per 100C. | |
| Sep 13, 2013 at 17:46 | history | edited | jdj081 | CC BY-SA 3.0 |
typographical error. I had an Omega where there shouldn't have been. Removed the Omega and clarified the sentence.
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| Sep 13, 2013 at 6:46 | comment | added | user80551 | So the correct answer is 300C? Also how did you arrive at "a slope of 0.005 Ω/∘C means 50 Ω per 100 ∘C." Why isn't it 0.5 ohm per 100C? | |
| Sep 13, 2013 at 6:42 | vote | accept | user80551 | ||
| Sep 13, 2013 at 6:42 | |||||
| Sep 13, 2013 at 6:07 | history | answered | jdj081 | CC BY-SA 3.0 |