Timeline for How is this approximation of gravity involving Rindler coordinates valid?
Current License: CC BY-SA 4.0
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| May 27 at 6:26 | comment | added | safesphere | “the Ricci scalar, which is a contraction of the curvature tensor, is supposed to be invariant” - The Ricci tensor and therefore the scalar are both zero in the Schwarzschild spacetime. The only curvature there is Weyl that defines the magnitude of the time dilation and length contraction, which are equal (or reciprocal depending on the view) to each other similarly to Special Relativity. Thus locally and radially the Schwarzschild spacetime is equivalent to Rindler, as it should be according to the Equivalence Principle. | |
| Jun 28, 2023 at 13:52 | history | edited | MaximusIdeal | CC BY-SA 4.0 |
added 120 characters in body
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| Jun 28, 2023 at 7:44 | answer | added | peek-a-boo | timeline score: 0 | |
| Jun 28, 2023 at 6:08 | history | asked | MaximusIdeal | CC BY-SA 4.0 |