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Jun 24, 2023 at 20:12 comment added Amit @belkarx You may be interested to take a look at this question (it isn't quite the same, but closely related): Maximal Gravity
Jun 24, 2023 at 19:06 comment added belkarx @Amit Yes, tidal forces can be neglected
Jun 24, 2023 at 19:05 comment added Amit @belkarx okay, and do you only consider the downward force towards the surface? Can one neglect "tidal forces" in an answer, e.g. ones that tend to "stretch" someone standing on the surface horizontally?
Jun 24, 2023 at 19:01 comment added belkarx Hey @Amit, I do mean "at at least one point" :)
Jun 24, 2023 at 18:46 comment added Amit @MichaelSeifert It's a very good guess and there's a high probability you're correct, but I would still prefer that be made as explicit as you made it ;)
Jun 24, 2023 at 18:44 comment added Michael Seifert @Amit: The OP says "the same gravity as Earth at a point", which I would interpret as "create a shape for which the gravitational acceleration has a magnitude of 9.8 m/s^2 at at least one point on its surface."
Jun 24, 2023 at 18:26 comment added Amit Welcome belkarx. I think you need to be more specific and describe what exactly you mean when you write "the same gravity as earth".. in the current accepted model of gravity which is GR the shape of the gravitating object also determines the gravitational field (or more precisely, the spacetime curvature) in its vicinity. Since the earth is very nearly a sphere (it's in fact an oblate spheroid) for example, the gravitational field is almost completely symmetric with respect to angular movement around it, so if you want to keep that feature too, you'll also need something similar.
S Jun 24, 2023 at 18:17 review First questions
Jun 24, 2023 at 18:27
S Jun 24, 2023 at 18:17 history asked belkarx CC BY-SA 4.0