Skip to main content
10 events
when toggle format what by license comment
Jun 17, 2023 at 19:49 comment added hyportnex From the very deep past what I can recall is that the issue is related to the fact the higher the wave the faster it is, thus a depression cannot be stable. This you can see by neglecting the dispersive term represented by the 3rd derivative $u_{xxx}$ and by writing the remainder of the KdV as $u_t+uu_x$ whose solution is $u=f(s)$ with $s=x-ut$ for any differentiable $f(s)$. This shows that the apparent nondispersive wave speed is $u$. In a trough the surrounding is always at a higher speed than the trough itself, so it cannot be stable.
Jun 17, 2023 at 16:35 history reopened hyportnex
MaximusIdeal
John Doty
Jun 17, 2023 at 16:05 history edited MaximusIdeal CC BY-SA 4.0
Added citation, added tags, improved title
Jun 17, 2023 at 14:16 comment added hyportnex This is a good question and its answer is nontrivial.
Jun 17, 2023 at 14:15 review Reopen votes
Jun 17, 2023 at 16:37
Jun 17, 2023 at 14:12 history closed anna v
Miyase
Jon Custer
Needs details or clarity
Jun 17, 2023 at 7:18 comment added Farcher A link to the Wikipedia article Dispersion (water waves) in section shallow water.
Jun 17, 2023 at 5:40 comment added FlatterMann Can you give a citation to the specific language in that page? Did they say that equations that produce solitons can not have an almost everywhere nearly constant non-zero solution with a stable "dip" in them?
Jun 17, 2023 at 4:20 review Close votes
Jun 17, 2023 at 14:12
Jun 17, 2023 at 2:41 history asked Abdullah is not an Amalekite CC BY-SA 4.0