Timeline for Is the way of determining my angle of vector wrong or am I using the wrong formula for calculating magnitude of resultant?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| May 19, 2023 at 19:31 | comment | added | nasu | Both formulas, for sum and difference, result from the cosine theorem. I am not sure what are you asking in your comment above. A and B here mean magnitudes. So the vertical bars make no difference. A and |A|are the same thing. The minus sign is not because vector B has negative magnitude! | |
| May 19, 2023 at 17:55 | comment | added | Machinexa | $R = |\vec{A} - \vec{B}| = \sqrt{(A^2 + B^2 + 2A(-B)Cos\theta)}$ vs $R = |\vec{A} - \vec{B}| = \sqrt{(|A^2| + |B^2| + 2|A||(-B)|Cos\theta)}$ Answer obviously wont match using latter but I wanted to know why absolute is used | |
| May 19, 2023 at 17:53 | comment | added | Machinexa | Btw do you think first formula to calculate magnitude is better than second formula. I saw some guys using absolute when finding R. | |
| May 19, 2023 at 17:44 | comment | added | Machinexa | So using $|\vec{A}+\vec{B}|$ was fault while angle being 180 was correct. Thanks | |
| May 19, 2023 at 17:41 | vote | accept | Machinexa | ||
| May 19, 2023 at 17:40 | history | answered | nasu | CC BY-SA 4.0 |