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Apr 20, 2023 at 17:28 vote accept TunaSandwich
Apr 19, 2023 at 19:41 answer added E. Anikin timeline score: 3
Apr 19, 2023 at 19:40 comment added ACuriousMind see physics.stackexchange.com/a/359982/50583
Apr 19, 2023 at 19:37 history edited Qmechanic
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Apr 19, 2023 at 19:15 comment added LPZ Intuitively, the small $dx$ comes from the fact that the kets $|x\rangle$ have infinite norm. Rather than being orthonormal, they satisfy:$$\langle y|x\rangle=\delta(x-y)$$ By dimensional analysis you can see that the discrete sum needs to be corrected by the small $dx$ to let the norms diverge. Naturally, this is a heuristic, but can be made rigorous by considering say a periodic box and letting its volume go to infinity.
Apr 19, 2023 at 18:34 comment added FlatterMann Technically it doesn't follow all that trivially. Physicists like to handwave these things into existence, but in mathematical reality you have to study the solution theory of quantum mechanical equations very carefully. To give you an idea of what is really involved in this, you can take a look at en.wikipedia.org/wiki/Spectrum_(functional_analysis). The complexity of the phenomenon shouldn't discourage you to learn more about the handwaving methods of physics. It's just to show that "proving" that they make sense is not easy.
Apr 19, 2023 at 18:14 comment added naturallyInconsistent You would have to construct a limiting process for each case. e.g. the case for momentum would be a different limiting process than for position. And yes, the factor of length will change the wavefunction's units and magnitude to compensate.
S Apr 19, 2023 at 18:10 review First questions
Apr 19, 2023 at 18:13
S Apr 19, 2023 at 18:10 history asked TunaSandwich CC BY-SA 4.0