Timeline for How to decompose Plasma ion Drag Force on a particle moving through it?
Current License: CC BY-SA 4.0
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| Apr 6, 2023 at 19:55 | comment | added | Lunthang Peter | @honeste_vivere, In the case of cle orbiting around a massive object such as the near the planets like Jupiter, Saturn etc the plasma drag, however small, do influence the its evolutions and dynamics. Even if there is no direct impact/collision 'coulomb drag' of the plasms too influence the charge dynamics and cannot be neglected. However, Plasma drag due to collsions and coulomb drag have similar expression except that the coulomb drag is much larger. | |
| Apr 6, 2023 at 13:11 | comment | added | honeste_vivere | The Coulomb collision rates at physics.stackexchange.com/a/268594/59023 are basically a probabilistic estimate of 90 degree scattering. In most non-lab plasmas outside of stellar surfaces, the collision rate between charged particles in a plasma is tiny to the point of being negligible for most processes of interest. That is, most interesting things happen much faster than Coulomb collisions, which is why shock waves in space are called collisionless shock waves. | |
| Apr 6, 2023 at 11:49 | history | edited | Lunthang Peter | CC BY-SA 4.0 |
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| Apr 5, 2023 at 20:32 | comment | added | Kyle Kanos | I imagine you'd start with the distribution and use the aforementioned scattering cross section and do some convolution of sorts (can't be more specific because it's not something I've done). Intuitively, I'd say that the scattering cross section for the perpendiculars is small & can be ignored (i.e., it'd be close enough to zero so as to be unimportant). | |
| Apr 5, 2023 at 19:59 | history | edited | Qmechanic♦ |
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| Apr 5, 2023 at 19:51 | history | edited | Lunthang Peter | CC BY-SA 4.0 |
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| Apr 5, 2023 at 19:44 | comment | added | Lunthang Peter | @KyleKanos, The reason I asked is to be able to find the drag/force for a particle moving along any direction. For instance, the plasma is at the origin of a Spherical polar Frame and pass through it at some radial distance, at ang co-latitude angle (θ) = 45degree and azimulth angle (ϕ) =60degree. How would I incorporate it in the drag equation? | |
| Apr 5, 2023 at 15:37 | comment | added | Kyle Kanos | Well that's all well and good after a collision. My comment was referring to the probability of a (perpendicular) collision happening in the first place. | |
| Apr 5, 2023 at 15:15 | comment | added | Lunthang Peter | The scattering angles both for large and small one, Impact parameter, only affect the strength of the force not the nature of the force. | |
| Apr 5, 2023 at 15:02 | comment | added | Kyle Kanos | I would imagine that the scattering cross sections along the perpendicular are small enough to be negligible. | |
| Apr 5, 2023 at 13:21 | history | asked | Lunthang Peter | CC BY-SA 4.0 |