The power of the car engine is

$$P=\tau\,\omega_E=\tau\,\frac{n\,\pi}{30}$$ where $~\tau~$ is the engine torque and $~n~$ is the speed of rotation $~[1/min]~$

from here you obtain the force that accelerate the car $$~F=a\tau~\quad, n=n_{P}$$ where $~n_P~$ is the speed of rotation in which you obtain $~\tau=\tau_{max}~$

with Newton second low the acceleration of the car

$$M\,a=F-\mu\,M\,g$$

where $~\mu\,M\,g~$ is the friction force and M is the total mass of the car

The power of the car engine is

$$P=\tau\,\omega_E=\tau\,\frac{n\,\pi}{30}$$ where $~\tau~$ is the engine torque and $~n~$ is the engine speed of rotation $~[1/min]~$

from here you obtain the force that accelerate the car $$~F=a\tau~\quad, n=n_{P}$$ where $~n_P~$ is the speed of rotation in which you obtain $~\tau=\tau_{max}~$

with Newton second low the acceleration of the car

$$M\,a=F-\mu\,M\,g$$

where $~\mu\,M\,g~$ is the friction force and M is the total mass of the car

The power of the car engine is

$$P=\tau\,\omega_E=\tau\,\frac{n\,\pi}{30}$$ where $~\tau~$ is the engine torque and $~n~$ is the speed of rotation $~[1/min]~$

from here you obtain the force that accelerate the car $~F=a\tau~\quad, n=n_{max}$

and with Newton second low you the acceleration of the car

$$M\,a=F-\mu\,M\,g$$

where $~\mu\,M\,g~$ is the friction force and M is the total mass of the car

The power of the car engine is

$$P=\tau\,\omega_E=\tau\,\frac{n\,\pi}{30}$$ where $~\tau~$ is the engine torque and $~n~$ is the speed of rotation $~[1/min]~$

from here you obtain the force that accelerate the car $$~F=a\tau~\quad, n=n_{P}$$ where $~n_P~$ is the speed of rotation in which you obtain $~\tau=\tau_{max}~$

with Newton second low the acceleration of the car

$$M\,a=F-\mu\,M\,g$$

where $~\mu\,M\,g~$ is the friction force and M is the total mass of the car