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Timeline for Why is $F$ defined as $ma$?

Current License: CC BY-SA 4.0

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May 18, 2018 at 19:11 comment added Shing @Nat the question is the kind of embarrassing silly questions i asked years ago, it would be hard for me to even read it (a bit too embarrassing and english a bit too sucky). nonetheless, I will probably edit and improve it in a few days.
May 14, 2018 at 11:13 history edited Qmechanic CC BY-SA 4.0
edited tags; edited title
May 14, 2018 at 11:09 comment added Nat The general topic is interesting and would seem to make for a good question, though have to -1 for now given the presentation.
May 14, 2018 at 11:06 history edited Nat CC BY-SA 4.0
edited title
May 14, 2018 at 11:03 comment added Nat Did a lot of editing, though wasn't able to parse the question well enough to do a full edit.
May 14, 2018 at 11:00 history edited Nat CC BY-SA 4.0
Partial reformatting, though much of the post seems unclear.
May 30, 2015 at 19:25 answer added danielsmw timeline score: 2
May 30, 2015 at 15:22 answer added sure timeline score: 0
S May 30, 2015 at 14:41 history edited HDE 226868 CC BY-SA 3.0
Edited LaTeX and formatting.
S May 30, 2015 at 14:41 history suggested NeilRoy CC BY-SA 3.0
changed spelling
May 30, 2015 at 14:22 review Suggested edits
S May 30, 2015 at 14:41
Aug 30, 2013 at 15:33 comment added udiboy1209 Yes, generality is an important factor for a law. By the way, newton's laws work for variable mass systems, but I doubt your equation will.
Aug 30, 2013 at 9:20 history edited Shing CC BY-SA 3.0
To improve my math for a better understanding
Aug 30, 2013 at 9:15 history edited Shing CC BY-SA 3.0
To improve my question thanks to some answers.
Aug 30, 2013 at 9:01 comment added Shing @udiboy, are you suggesting generality as a importance factor for constructing a equation? I am just self learning how to construct a theory, and I picked newton mechanics simply because it is the simplest physics theory that I know,,and sure the new equations don't apply well, whenever the Newton Mechanics doesn't.
Aug 30, 2013 at 5:21 comment added udiboy1209 $F$ is more correctly defined as $\frac{dP}{dt}$ where $P$ is the momentum. You are assuming mass $m$ to be a contant, but do your equations work well for variable mass systems(when $m$ is not constant, eg. rocket engines)? What about forces on massless objects which have momentum, like light?
Aug 30, 2013 at 4:13 answer added XL _At_Here_There timeline score: 0
Aug 29, 2013 at 23:57 comment added John Alexiou Because it works.
Aug 29, 2013 at 23:50 answer added user4552 timeline score: 3
Aug 29, 2013 at 20:02 history edited Shing CC BY-SA 3.0
edited title
Aug 29, 2013 at 19:57 history edited Shing CC BY-SA 3.0
corrected a big mistake
Aug 29, 2013 at 19:44 history edited Shing CC BY-SA 3.0
added 6 characters in body
Aug 29, 2013 at 19:33 history edited Shing CC BY-SA 3.0
edited body
Aug 29, 2013 at 19:32 comment added Qmechanic Related: physics.stackexchange.com/q/4471/2451 and links therein.
Aug 29, 2013 at 19:28 history edited Shing CC BY-SA 3.0
just to make it more readable
Aug 29, 2013 at 19:17 history asked Shing CC BY-SA 3.0