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Aug 23, 2013 at 19:22 answer added gatsu timeline score: 1
Aug 23, 2013 at 17:28 comment added physguy My intuition also tells me it should be independent of $N$. However, if all the electrons are independent, the probability should follow a binomial distribution, so that the probability would be $N!/((0.75N)!(0.25N)!) \; p^{0.75N} (1-p)^{0.25N}$, where $p$ is the probability of one electron to have energy $E_+$. This does depend on $N$ though...
Aug 23, 2013 at 11:15 comment added gatsu I don't get it, if you imagine your $N$ electrons to be independent, then the probability you are looking for is independent on $N$. You just want that $e^{-\beta E_+}/\xi = 0.75$ don't you?
Aug 23, 2013 at 0:27 answer added joshphysics timeline score: 1
Aug 22, 2013 at 23:11 history asked physguy CC BY-SA 3.0