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Thomas
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A perfect fluid is in local thermal equilibrium, and the velocity distribution must be the one given by the equilibrium partition function. For a non-interacting gas this is the Maxwell-Juttner distribution. In thermal equilibrium the fluid is completely characterized by thermodynamic variables, for example energy density and pressure, and symmetries fix the form of the stress tensor, $T_{\mu\nu}=(e,p,p,p)$ in the local rest frame. The stress tensor is the only input required by GR.

A perfect fluid is in local thermal equilibrium, and the velocity distribution must be the one given by the equilibrium partition function. For a non-interacting gas this is the Maxwell-Juttner distribution.

A perfect fluid is in local thermal equilibrium, and the velocity distribution must be the one given by the equilibrium partition function. For a non-interacting gas this is the Maxwell-Juttner distribution. In thermal equilibrium the fluid is completely characterized by thermodynamic variables, for example energy density and pressure, and symmetries fix the form of the stress tensor, $T_{\mu\nu}=(e,p,p,p)$ in the local rest frame. The stress tensor is the only input required by GR.

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Thomas
  • 19k
  • 1
  • 32
  • 61

A perfect fluid is in local thermal equilibrium, and the velocity distribution must be the one given by the equilibrium partition function. For a non-interacting gas this is the Maxwell-Juttner distribution.