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Jan 29, 2023 at 14:53 comment added Peltio If you accept the fact the Ohm's laws is locally obeyed in the low conductivity resistor and the high conductivity wires, you reach the conclusion that since current density j is the same in both (we must obey the continuity equation), the electric field E = j/sigma must be higher in the resistor and smaller in the wires. Then all you need is Gauss law applied to a closed surface enclosing the interface between the materials to show that you need charge at the interface. It has to be there in steady state to justify the nonzero electric flux.
Jan 29, 2023 at 5:25 history edited Qmechanic CC BY-SA 4.0
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Jan 28, 2023 at 22:57 answer added Cleonis timeline score: 2
Jan 28, 2023 at 9:53 history edited Jaime Yepes de Paz CC BY-SA 4.0
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Jan 28, 2023 at 9:44 history asked Jaime Yepes de Paz CC BY-SA 4.0