Timeline for What actually causes the electromagnetic field to be quantized?
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
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| Apr 2, 2023 at 16:48 | comment | added | Quillo | Closely related: physics.stackexchange.com/q/542460/226902 and links therein. Experiments on EM field quantization: physics.stackexchange.com/q/372813/226902 | |
| Jan 23, 2023 at 19:59 | history | reopened |
hyportnex Michael Seifert John Rennie |
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| Jan 23, 2023 at 10:48 | review | Reopen votes | |||
| Jan 23, 2023 at 19:59 | |||||
| Jan 23, 2023 at 8:08 | comment | added | Bill Alsept | The short answer, Light is made of individual photons with energies/frequencies across the spectrum. Blue light is made of billions of individual photons with frequencies somewhere around 6.66 ✕ 10¹⁴ Hz | |
| Jan 23, 2023 at 6:56 | history | closed |
joseph h Miyase anna v |
Needs details or clarity | |
| Jan 23, 2023 at 4:47 | vote | accept | Mikayla Eckel Cifrese | ||
| Jan 23, 2023 at 4:47 | |||||
| Jan 23, 2023 at 4:36 | answer | added | DanielSank | timeline score: 7 | |
| Jan 23, 2023 at 4:25 | history | edited | Mikayla Eckel Cifrese | CC BY-SA 4.0 |
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| Jan 23, 2023 at 4:13 | answer | added | Ryder Rude | timeline score: 0 | |
| Jan 23, 2023 at 4:12 | comment | added | DanielSank | This question is a classic confusion about quantization of available states, which does indeed come from boundary conditions but is a classical effect, and quantization of excitations, which is purely a quantum effect. I suggest reading this other question. | |
| Jan 23, 2023 at 2:56 | history | edited | Qmechanic♦ |
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| Jan 23, 2023 at 2:48 | review | Close votes | |||
| Jan 23, 2023 at 7:00 | |||||
| Jan 23, 2023 at 2:25 | comment | added | joseph h | Photons that are emitted from atoms/molecules (due to electrons changing energy levels) have specific energies. The idea that all photons have discrete energies is incorrect. | |
| Jan 23, 2023 at 2:20 | comment | added | Gold | Photons do not necessarily have discrete energy levels. In QFT photon states are labelled as $|p,\sigma\rangle$ where $\sigma=\pm 1$ is the photon helicity and where $p$ is a null four-vector, i.e., a tuple $p = (p^0,p^1,p^2,p^3)$ such that $$p^2=-(p^0)^2+(p^1)^2+(p^2)^2+(p^3)^2=0.$$ In that setting the energy of the photon is $p^0$ and it can be really anything. | |
| Jan 23, 2023 at 2:10 | history | asked | Mikayla Eckel Cifrese | CC BY-SA 4.0 |