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Jan 19, 2023 at 23:06 vote accept realGuybrush
Jan 19, 2023 at 23:06 comment added realGuybrush Thank you very much for your answer. Perhaps my question was not perfectly correct, because Townsend Discharge was not exactly what I was looking for. But it gave me a push in a right direction: it is field emission, especially cold field emission. The formulas in question most likely are: $ r = \frac \alpha A * U^\frac 3 2$ and $ E_0 = U*(\frac {1-\alpha}{\frac r 4 * \ln{\frac {4R} r}}+\frac \alpha r)$, where A - work function, r - tip radius, $\alpha$ - tip shape-based constant (roughly 0,1 in this case), U - voltage needed for discharge, $E_0$ - field at the tip, R - anode-cathode distance.
Jan 12, 2023 at 5:46 review Low quality answers
Jan 12, 2023 at 7:15
Jan 12, 2023 at 5:28 history answered niels nielsen CC BY-SA 4.0