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Jan 13, 2023 at 11:23 vote accept Authentic Melody
Jan 13, 2023 at 11:23 vote accept Authentic Melody
Jan 13, 2023 at 11:23
Jan 12, 2023 at 17:55 answer added John Rennie timeline score: 3
Jan 12, 2023 at 8:21 history edited Authentic Melody CC BY-SA 4.0
added 29 characters in body; edited title
Jan 11, 2023 at 18:12 history edited Authentic Melody CC BY-SA 4.0
added 93 characters in body; edited title
Jan 11, 2023 at 16:13 history edited John Rennie CC BY-SA 4.0
Tweak
Jan 11, 2023 at 15:36 comment added Jon Custer For a particular reaction, you look at the Q value - the energy required or released. Go to ENSDF (say nndc.bnl.gov/ensdf), enter 234, find the U238 alpha decay, and note that Q = 4269.7 keV - it is exothermic.
Jan 11, 2023 at 15:07 comment added Jon Custer Why is binding energy per nucleon even a worry here - the real point is an overall energy balance. But, you know that there are at least some reactions from splitting up U238 into daughter products that will result in an overall energy release.
Jan 11, 2023 at 14:42 history asked Authentic Melody CC BY-SA 4.0