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Since the solution of the wave function in vaccum gives two progressive plane waves f(x-ct)+g(x+ct)$f(x-ct)+g(x+ct)$ depending on x$x$ the direction of propagation, in the other side we have the div(Ex)=0$\operatorname{div}(Ex)=0$ so the E$E$ field is static so the wave is not propagating!!!. I can't understand the reasoning here and How this explain that the wave is transverse

Since the solution of the wave function in vaccum gives two progressive plane waves f(x-ct)+g(x+ct) depending on x the direction of propagation, in the other side we have the div(Ex)=0 so the E field is static so the wave is not propagating!!!. I can't understand the reasoning here and How this explain that the wave is transverse

Since the solution of the wave function in vaccum gives two progressive plane waves $f(x-ct)+g(x+ct)$ depending on $x$ the direction of propagation, in the other side we have the $\operatorname{div}(Ex)=0$ so the $E$ field is static so the wave is not propagating!!!. I can't understand the reasoning here and How this explain that the wave is transverse

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Couldn't understand the reasoning on the propagation of the electromagnetic wave in the vacuum?

Since the solution of the wave function in vaccum gives two progressive plane waves f(x-ct)+g(x+ct) depending on x the direction of propagation, in the other side we have the div(Ex)=0 so the E field is static so the wave is not propagating!!!. I can't understand the reasoning here and How this explain that the wave is transverse