Timeline for Doesn't $F=ILB$ violate the conservation of energy?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Nov 26, 2022 at 10:46 | vote | accept | neel g | ||
| Nov 25, 2022 at 18:53 | comment | added | Jim | @neelg $B$ is not a measure of energy directly. To generate a magnetic field using, say, a wire is easy. However, if that magnetic field would interact with another object such that there's a transfer of energy, that acts like increased resistance in the wire. You need to pump in more voltage (energy) to run it. Having a constant $B$ is not the same thing as a constant input of energy | |
| Nov 25, 2022 at 17:53 | answer | added | Dale | timeline score: 2 | |
| Nov 25, 2022 at 17:27 | history | edited | neel g | CC BY-SA 4.0 |
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| Nov 25, 2022 at 17:24 | comment | added | neel g | @Jim The source of the external $B$ could be set constant - i.e, there is a constant amount of energy going into the system in the form of the $B$ electric field. You could generate it with a variety of apparatus. What matters it that the energy input-ted is the same. The definition of $B$ is defined per unit length of the conductor, so you can assume that is indeed constant. | |
| Nov 25, 2022 at 15:50 | review | Close votes | |||
| Nov 26, 2022 at 10:51 | |||||
| Nov 25, 2022 at 15:34 | comment | added | Dale | The geometry of this is unclear. Are you intending a straight conductor? If so are you allowing charge to build up at the end or do you have a return path of some sort that you are neglecting? Or are you intending the wire to form a loop? In which case a different formula would be more appropriate. Please edit the question to clarify | |
| Nov 25, 2022 at 14:46 | comment | added | Jim | What is generating your external $B$ field? Is it possible that this is providing a source of energy? The scenario with $kL$ is no more a violation of conservation of energy than the scenario without $k$. Where did the energy transferred to the wire come from in the first case? It's safe to say the energy in the second case comes from the same source, it simply draws more energy from that source | |
| Nov 25, 2022 at 14:26 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
edited title
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| Nov 25, 2022 at 14:09 | history | asked | neel g | CC BY-SA 4.0 |