Timeline for Do all objects at the same temperature glow the same color?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Nov 20, 2022 at 21:50 | history | edited | Massimo Ortolano | CC BY-SA 4.0 |
added 1 character in body
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| Nov 19, 2022 at 15:10 | comment | added | Neil Libertine | I think Kirchoff law is about two or more bodies at same temperature and in thermal equilibirium, the ratio of any two bodies emissivity is equals to ratio of absorpitivity. Yes, Planck law is about black body. And there is no need to absorb radiation when passing current or excitation by current can produce radiation. | |
| Nov 19, 2022 at 10:57 | comment | added | Peter Bernhard | The "black" is for counting out all "natural colour" that a body's heat is not cause of? What Mark says I understand as some requirement of minimum heat for emission of "colour" that is not only "non-absorption" (considering complementary natural colours of object). In other words there must be some heat, and, paradoxically, that is more important than the body having no other color, being black. | |
| Nov 19, 2022 at 3:43 | comment | added | Mark | The hotter something gets, the better it approximates a blackbody. Iron melts at 1800 K, which gives it a reasonably blackbody spectrum. | |
| Nov 18, 2022 at 23:32 | comment | added | James | Thank you! Is Kirchoff law equivalent to the statement that, for example, all coal at the same temperature will glow the same color? Since all materials "which absorbs all incident electromagnetic radiation" can be treated essentially as the same object spectroscopically, then Kirchoff law states that all objects with the same absorption/reflection properties will glow the same color at the same temperature? | |
| Nov 18, 2022 at 18:07 | history | answered | gandalf61 | CC BY-SA 4.0 |