Timeline for Can a set of states be orthonormal, but not complete?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Nov 17, 2022 at 13:54 | comment | added | mmesser314 | +1, but a better example might have been $\mathbb{C}^3$ and the set $(1,0,0)$ and $(0,1,0)$. These are more obviously orthonormal but not complete. | |
| Nov 17, 2022 at 13:20 | vote | accept | schris38 | ||
| Nov 17, 2022 at 13:20 | comment | added | schris38 | Okay thanks @MichaelSeifert | |
| Nov 17, 2022 at 13:00 | comment | added | Michael Seifert | @schris38: Setting aside the double negatives: A set of vectors can be (a) mutually orthogonal, (b) a basis for the space they're a part of, (c) both, or (d) neither. All options are possible. | |
| Nov 17, 2022 at 12:58 | comment | added | schris38 | So, not being complete does not necessarily mean that they are not orthogonal, or am I wrong? | |
| Nov 17, 2022 at 12:48 | history | answered | Janik | CC BY-SA 4.0 |