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Oct 26, 2022 at 14:04 comment added user7077252 The sample is thinner than the wavelength, as the wavelength of the signal is around 100 $\mu$m and the sample is around 6 $\mu$m thick. Doesn't this have an effect on the mathematical approach?
Oct 26, 2022 at 13:50 comment added mmesser314 +1, but "a few wavelengths thick" is thicker than usual. For example, an anti-reflection coating would be $1/4$ wave thick, so the wave traveling to the rear surface and back travels an extra $1/2$ wavelength and destructively interferes with the front wave.
Oct 26, 2022 at 13:47 history answered John CC BY-SA 4.0