Timeline for How to obtain the refractive index of a thin film via reflection?
Current License: CC BY-SA 4.0
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Oct 26, 2022 at 14:04 | comment | added | user7077252 | The sample is thinner than the wavelength, as the wavelength of the signal is around 100 $\mu$m and the sample is around 6 $\mu$m thick. Doesn't this have an effect on the mathematical approach? | |
Oct 26, 2022 at 13:50 | comment | added | mmesser314 | +1, but "a few wavelengths thick" is thicker than usual. For example, an anti-reflection coating would be $1/4$ wave thick, so the wave traveling to the rear surface and back travels an extra $1/2$ wavelength and destructively interferes with the front wave. | |
Oct 26, 2022 at 13:47 | history | answered | John | CC BY-SA 4.0 |