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Oct 1, 2022 at 17:17 comment added user292464 Could you please write down the expression for both the solutions. Are they simply $Ae^{\xi^2/2}$ and $Be^{-\xi^2/2}$? After this the author proceeds to discard the former as it diverges and then he uses power series to derive those normalizeable $\psi(x)$s (the hermite ones).
Oct 1, 2022 at 11:11 history answered mike stone CC BY-SA 4.0