Timeline for Geometric interpretation of tensor product
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 23, 2022 at 0:13 | history | edited | Qmechanic♦ |
edited tags
|
|
| Sep 22, 2022 at 22:13 | comment | added | Ghoster | Although I don’t know of a geometric interpretation, tensor algebra does have a physical interpretation in terms of the quantum state of multiple non-interacting quantum objects. If object $A$ has state $|A\rangle$ and similarly for B, then if they don’t interact the quantum state of the system is $|A\rangle\otimes|B\rangle$. | |
| Sep 22, 2022 at 21:08 | vote | accept | CBBAM | ||
| Sep 22, 2022 at 21:03 | answer | added | Cosmas Zachos | timeline score: 2 | |
| Sep 22, 2022 at 20:54 | comment | added | CBBAM | @Ghoster Thank you I will take a look at exterior algebras, I'm not familiar with them at the moment. I suppose I will just have to consider tensor algebras are purely algebraic with no physical or geometric interpretation. | |
| Sep 22, 2022 at 20:31 | comment | added | Ghoster | Exterior algebra, which is related to tensor algebra, has an intuitive geometric interpretation. In my opinion, tensor algebra itself doesn’t. But there is no reason that it should. It seems to me to be natural (in the vague, undefined sense of that word) algebraically but not geometrically. | |
| Sep 22, 2022 at 20:23 | history | edited | CBBAM | CC BY-SA 4.0 |
edited body
|
| Sep 22, 2022 at 20:09 | history | edited | CBBAM | CC BY-SA 4.0 |
added 49 characters in body
|
| Sep 22, 2022 at 20:02 | history | asked | CBBAM | CC BY-SA 4.0 |