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Aug 24, 2022 at 6:25 comment added Kashmiri In above comment i meant $\mathbf{\hat{x}} |\mathbf{x}' \rangle = \mathbf{{x}} |\mathbf{x} \rangle$
Aug 23, 2022 at 16:28 comment added Kashmiri So $\mathbf{\hat{x}} |\mathbf{x}' \rangle = \mathbf{\hat{x}} |\mathbf{x} \rangle$ means nothing but three separate eigenvalue equations? The vector operator is just an abbreviation to condense the three equations?
Aug 23, 2022 at 16:13 comment added Kashmiri Thank you so much.
Aug 23, 2022 at 13:41 history answered J. Murray CC BY-SA 4.0