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RC_23
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If I understand your assumption that all of the matter objects are similar, and all on a large scale have similar densities, then what determines one's velocity from us is determined by the equation:

V = D x H_0.$$V = D * H_0. $$

V$V$ is velocity formfrom us, D$D$ is distance from us, and H_0$H_0$ is the Hubble constant with the reciprocal value: 1/H_0 = 14.4 Gyrs$1/H_0 = 14.4 \, \text {Gyrs}$.

So, what needs to be calculated is the average of distance A of points within a sphere from its center. The radius of the sphere R will be

R = c x 14.4 Gyrs. $$R = c * 14.4 \, \text {Gyrs}. $$ (Note: c = speed of light.)

I think you that should have the first try to calculating A. If you can't solve for A, then I will offer some more help.

The reason for this value of R (also known as the event horizon) is that the distance R is where anything further away travels away from the center faster than the speed of light.

If I understand your assumption that all of the matter objects are similar, and all on a large scale have similar densities, then what determines one's velocity from us is determined by the equation:

V = D x H_0.

V is velocity form us, D is distance from us, and H_0 is the Hubble constant with the reciprocal value: 1/H_0 = 14.4 Gyrs.

So, what needs to be calculated is the average of distance A of points within a sphere from its center. The radius of the sphere R will be

R = c x 14.4 Gyrs. (Note: c = speed of light.)

I think you that should have the first try to calculating A. If you can't solve for A, then I will offer some more help.

The reason for this value of R (also known as the event horizon) is that the distance R is where anything further away travels away from the center faster than the speed of light.

If I understand your assumption that all of the matter objects are similar, and all on a large scale have similar densities, then what determines one's velocity from us is determined by the equation:

$$V = D * H_0. $$

$V$ is velocity from us, $D$ is distance from us, and $H_0$ is the Hubble constant with the reciprocal value: $1/H_0 = 14.4 \, \text {Gyrs}$.

So, what needs to be calculated is the average of distance A of points within a sphere from its center. The radius of the sphere R will be

$$R = c * 14.4 \, \text {Gyrs}. $$ (Note: c = speed of light.)

I think you that should have the first try to calculating A. If you can't solve for A, then I will offer some more help.

The reason for this value of R (also known as the event horizon) is that the distance R is where anything further away travels away from the center faster than the speed of light.

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Buzz
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If I understand your assumption that all of the matter objects are similar, and all on a large scale have similar densities, then what determines one's velocity from us is determined by the equation:

V = D x H_0.

V is velocity form us, D is distance from us, and H_0 is the Hubble constant with the reciprocal value: 1/H_0 = 14.4 Gyrs.

So, what needs to be calculated is the average of distance A of points within a sphere from its center. The radius of the sphere R will be

R = c x 14.4 Gyrs. (Note: c = speed of light.)

I think you that should have the first try to calculating A. If you can't solve for A, then I will offer some more help.

The reason for this value of R (also known as the event horizon) is that the distance R is where anything further away travels away from the center faster than the speed of light.