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Timeline for QFT-style vs. (NR)QM-style [closed]

Current License: CC BY-SA 4.0

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Aug 10, 2022 at 21:30 history edited Davius CC BY-SA 4.0
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Aug 7, 2022 at 3:24 history left closed in review Miyase
Michael Seifert
ZeroTheHero
Needs more focus
Aug 6, 2022 at 18:27 comment added hft So.... What textbook are you referring to?
Aug 6, 2022 at 14:24 review Reopen votes
Aug 7, 2022 at 3:24
Aug 6, 2022 at 14:24 history edited Davius CC BY-SA 4.0
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Aug 6, 2022 at 6:02 comment added GiorgioP-DoomsdayClockIsAt-90 @hft Wikipedia is a great resource. But not as authoritative as a good textbook on infinite-dimensional vector spaces. The issue is similar to claiming that a tensor space is not a special case of vector space.
Aug 6, 2022 at 1:27 history closed Níckolas Alves
hft
Cosmas Zachos
Needs more focus
Aug 6, 2022 at 1:11 comment added hft @FreeAssange Mkay whatever you say. Not sure if you clicked on the link to wikipedia: "Informally, a Fock space is the sum of a set of Hilbert spaces..."
Aug 6, 2022 at 0:23 comment added FreeAssange @hft A Fock space is a special case of a Hilbert space. While the precise structure of the Hilbert space of interacting field theories is an open question, we know that it is not a Fock space. So, in fact, it is more accurate to refer to the Hilbert space of a QFT rather than to its Fock space (which would only make sense for a free QFT).
Aug 6, 2022 at 0:10 history edited Davius CC BY-SA 4.0
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Aug 6, 2022 at 0:06 review Close votes
Aug 6, 2022 at 1:32
Aug 6, 2022 at 0:05 comment added hft "Why did we never ask..." Who is "we"? Why do you assume we didn't ask such questions?
Aug 6, 2022 at 0:04 comment added hft @Davius You often don't use a Hilbert Space in QFT, you use a Fock Space (for states with changing particle number). en.wikipedia.org/wiki/Fock_space
Aug 6, 2022 at 0:02 comment added Gold The Hilbert space of a relativistic QFT must by definition carry a unitary representation of the universal cover of the Poincaré group - that is a constraint of relativistic symmetry. The issue is that finding such a Hilbert space and the corresponding representation in a complete interacting theory is a very intricate open problem. Nevertheless, in free theories the problem is tractable, and when discussing the scattering problem such construction can still be used asymptotically. For a very good description of this see Weinberg's QFT textbook, volume 1, chapters 2 and 3.
Aug 5, 2022 at 23:43 history asked Davius CC BY-SA 4.0