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AlmostClueless
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Your second calculation is wrong. Basically because you have to be a little bit more careful what you are taking the trace of! You use the anti-commutation relations for the Dirac matrices, which is commonly written down like $$ \{\gamma^\mu, \gamma^\nu\} = 2 g^{\mu\nu}, $$ which is actually a bit sloppy. There is a $\mathbb I$ missing. You can easily see this observing that on the left there are matrices (which are entries of a 4-vector) and on the right there is only an entry of a tensor so there must be the identity. Hence you end up with $$ \text{tr}(\gamma^\mu \gamma^\nu) = \text{tr}(\{\gamma^\mu, \gamma^\nu\} - \gamma^\mu \gamma^\nu) = \text{tr}(2g^{\mu\nu}\mathbb I) -\text{tr}(\gamma^\mu\gamma^\nu) $$ $$ \implies\text{tr}(\gamma^\mu\gamma^\nu) = \frac{2}{2} \text{tr}(g^{\mu\nu} \mathbb I)=4g^{\mu\nu} $$ See also chapter 3.2 in "An Introduction to Quantum Field Theory" by M. Peskin and D.Schröder. (In my edition it is page 40)

Your second calculation is wrong. Basically because you have to be a little bit more careful what you are taking the trace of! You use the anti-commutation relations for the Dirac matrices, which is commonly written down like $$ \{\gamma^\mu, \gamma^\nu\} = 2 g^{\mu\nu}, $$ which is actually a bit sloppy. There is a $\mathbb I$ missing. You can easily see this observing that on the left there are matrices (which are entries of a 4-vector) and on the right there is only an entry of a tensor so there must be the identity. Hence you end up with $$ \text{tr}(\gamma^\mu \gamma^\nu) = \text{tr}(\{\gamma^\mu, \gamma^\nu\} - \gamma^\mu \gamma^\nu) = \text{tr}(2g^{\mu\nu}\mathbb I) -\text{tr}(\gamma^\mu\gamma^\nu) $$ $$ \implies\text{tr}(\gamma^\mu\gamma^\nu) = \frac{2}{2} \text{tr}(g^{\mu\nu} \mathbb I)=4g^{\mu\nu} $$

Your second calculation is wrong. Basically because you have to be a little bit more careful what you are taking the trace of! You use the anti-commutation relations for the Dirac matrices, which is commonly written down like $$ \{\gamma^\mu, \gamma^\nu\} = 2 g^{\mu\nu}, $$ which is actually a bit sloppy. There is a $\mathbb I$ missing. You can easily see this observing that on the left there are matrices (which are entries of a 4-vector) and on the right there is only an entry of a tensor so there must be the identity. Hence you end up with $$ \text{tr}(\gamma^\mu \gamma^\nu) = \text{tr}(\{\gamma^\mu, \gamma^\nu\} - \gamma^\mu \gamma^\nu) = \text{tr}(2g^{\mu\nu}\mathbb I) -\text{tr}(\gamma^\mu\gamma^\nu) $$ $$ \implies\text{tr}(\gamma^\mu\gamma^\nu) = \frac{2}{2} \text{tr}(g^{\mu\nu} \mathbb I)=4g^{\mu\nu} $$ See also chapter 3.2 in "An Introduction to Quantum Field Theory" by M. Peskin and D.Schröder. (In my edition it is page 40)

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AlmostClueless
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Your second calculation is wrong. Basically because you have to be a little bit more careful what you are taking the trace of! You use the anti-commutation relations for the Dirac matrices, which is commonly written down like $$ \{\gamma^\mu, \gamma^\nu\} = 2 g^{\mu\nu}, $$ which is actually a bit sloppy. There is a $\mathbb I$ missing. You can easily see this observing that on the left there are matrices (which are entries of a 4-vector) and on the right there is only an entry of a tensor so there must be the identity. Hence you end up with $$ \text{tr}(\gamma^\mu \gamma^\nu) = \text{tr}(\{\gamma^\mu, \gamma^\nu\} - \gamma^\mu \gamma^\nu) = \text{tr}(2g^{\mu\nu}\mathbb I) -\text{tr}(\gamma^\mu\gamma^\nu) $$ $$ \implies\text{tr}(\gamma^\mu\gamma^\nu) = \frac{2}{2} \text{tr}(g^{\mu\nu} \mathbb I)=4g^{\mu\nu} $$