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Jul 10, 2022 at 8:15 vote accept Mauro Giliberti
Jul 9, 2022 at 17:51 comment added Qmechanic Coleman's action $S_E$ is relative, i.e. a difference between the absolute action of different instanton sectors.
Jul 9, 2022 at 16:58 comment added Mauro Giliberti I don't understand at what point exactly in your answer the value of the action becomes important. The fact that the action in Coleman's example is the one of a single instanton shouldn't make a difference, right? A shift of the action of a single instanton shouldn't be physically relevant. Is the normalization choice that's not invariant? Could you highlight, in your answer, why a generic action is shift invariant but Coleman's one isn't?
Jul 9, 2022 at 8:54 comment added Qmechanic I updated the answer.
Jul 9, 2022 at 8:52 history edited Qmechanic CC BY-SA 4.0
Added explanation
Jul 9, 2022 at 0:00 comment added Mauro Giliberti this changes a lot of what I thought I understood. How is Coleman's Euclidean action different from the action in the path integral? It must be different, since a shift of Coleman's action is relevant, while a shift of the path integral's action isn't. Is it the fact that in the path integral I integrate the action, but I don't integrate the content of Coleman's one? If that's the case, I'd be more inclined to say that it's the integration that's invariant under overall shifts, not the action itself, therefore I suspect this isn't the correct reasoning.
Jul 8, 2022 at 19:23 history edited Qmechanic CC BY-SA 4.0
Added explanation
Jul 8, 2022 at 19:23 comment added Qmechanic An overall shift of the action in the path integral or the statistical partition function is not physical relevant as well.
Jul 8, 2022 at 15:49 history edited Qmechanic CC BY-SA 4.0
Added explanation
Jul 8, 2022 at 15:42 vote accept Mauro Giliberti
Jul 8, 2022 at 23:55
Jul 8, 2022 at 15:40 comment added Mauro Giliberti So the action is classically used only as a functional to be minimized, and so classical physics is invariant if $S\rightarrow S+5$, while the quantum path integral uses the value of the action to compute probability amplitudes, that therefore are not invariant if $S\rightarrow S+5$? It's the quantumness that seals the deal, not the Euclideaness, right?
Jul 8, 2022 at 15:21 history answered Qmechanic CC BY-SA 4.0