Timeline for Non-conservative force, but equation of harmonic motion
Current License: CC BY-SA 4.0
19 events
| when toggle format | what | by | license | comment | |
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| S Jul 3, 2022 at 5:31 | history | bounty ended | insipidintegrator | ||
| S Jul 3, 2022 at 5:31 | history | notice removed | insipidintegrator | ||
| Jul 3, 2022 at 5:31 | vote | accept | insipidintegrator | ||
| Jun 29, 2022 at 17:17 | answer | added | Stevan V. Saban | timeline score: 0 | |
| Jun 29, 2022 at 13:51 | answer | added | rob♦ | timeline score: 2 | |
| Jun 27, 2022 at 17:36 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
added 2 characters in body
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| S Jun 27, 2022 at 17:28 | history | bounty started | insipidintegrator | ||
| S Jun 27, 2022 at 17:28 | history | notice added | insipidintegrator | Improve details | |
| Jun 26, 2022 at 8:01 | history | edited | insipidintegrator | CC BY-SA 4.0 |
Status update
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| Jun 25, 2022 at 20:28 | comment | added | insipidintegrator | Thanks @J.Murray for taking the time to clear it up. | |
| Jun 25, 2022 at 20:21 | comment | added | J. Murray | Yes, the acceleration will always be nonzero. $x$ is the distance covered, so it cannot be negative; clearly $-(\mu_0 + kx)g <0$ (until the disc comes to a stop). | |
| Jun 25, 2022 at 20:15 | comment | added | insipidintegrator | @J.Murray I may come off as annoying, but pleaseeee confirm that even when the disc has started from a point (say A) with nonzero initial speed, there may be acceleration at A? I just feel silly asking this, but please confirm this for me. | |
| Jun 25, 2022 at 20:03 | comment | added | J. Murray | When $x=0$, we have $a = -(\mu_0 + k\cdot 0 )g = -\mu_0 g\neq 0$. The equilibrium point will be at $x= -k/\mu_0$. You could use some concepts from SHM, but it would not be quite as simple as just doing the integral. | |
| Jun 25, 2022 at 18:03 | comment | added | insipidintegrator | Ah….I see… At the expected mean position the acceleration is not 0 (as it should be in SHM). Or is it? Because we start from there. So at x=0, is a=0? @J.Murray can you please see if the question be solved via some SHM-concepts? | |
| Jun 25, 2022 at 18:01 | comment | added | insipidintegrator | Uh… @J.Murray why would that affect any calculations? It doesn't change $\omega$ | |
| Jun 25, 2022 at 17:58 | comment | added | J. Murray | You're right that the equation of motion is kinda SHM-like, but your analysis seems to proceed as though it is exactly SHM. What happened to the $\mu_0$ term? | |
| Jun 25, 2022 at 17:45 | history | edited | insipidintegrator | CC BY-SA 4.0 |
edited body
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| Jun 25, 2022 at 17:28 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
edited tags
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| Jun 25, 2022 at 17:21 | history | asked | insipidintegrator | CC BY-SA 4.0 |