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let'sLet's take an example wavesignal: $Y=Cos(x)$$y=\cos(x)$ about $x=0$.
$dy/dx=-Sin(0)=0$$\frac{dy}{dx}=-\sin(0)=0$;
$d2y/dx2=-Cos(0)=-1$$\frac{d^2y}{dx^2}=-\cos(0)=-1$.
itIt is important to note that one is not simply the square of the other.
let's take an example wave $Y=Cos(x)$ about $x=0$.
$dy/dx=-Sin(0)=0$
$d2y/dx2=-Cos(0)=-1$
it is important to note that one is not simply the square of the other
Let's take an example signal: $y=\cos(x)$ about $x=0$.
$\frac{dy}{dx}=-\sin(0)=0$;
$\frac{d^2y}{dx^2}=-\cos(0)=-1$.
It is important to note that one is not simply the square of the other.
