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Dec 7 at 16:01 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Aug 6 at 6:02 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Apr 4 at 10:05 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jan 11, 2023 at 16:37 answer added Hans Wurst timeline score: 0
May 30, 2022 at 15:17 comment added Cedric Chia I still don't fully understand this. Could you also have a look at another question that I posted: link? I explained my question in more details there with graphics
May 30, 2022 at 2:29 comment added Meng Cheng Sure, that's not an issue. Any two states in the same Hilbert space (square-integrable functions on $\mathbb{R}$) have an overlap.
May 30, 2022 at 0:43 comment added Cedric Chia Thank you for your help @MengCheng , I understand two harmonic oscillators that are displaced with respect to each other can be related by a displacement operator. However, is this case the frequency is also different.
May 29, 2022 at 14:01 comment added Meng Cheng You have already given the relation between them: $x_e=x_g-x_0, p_e=p_g$, so $H_e$ is just a displaced $H_e$. $|n_g\rangle$ and $|n_e\rangle$ are two different states in the same Hilbert space and there is an overlap between them.
May 29, 2022 at 13:51 history asked Cedric Chia CC BY-SA 4.0