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What you have done is correct. We have to judge the diagram by obtaining the results from the formula but not just simply imagining a diagram. The results suggest that your diagram was wrong and the correct diagram could be the below one:

enter image description here


Extending the comments:
To get a real image the virtual object should lie in between pole and the focus. We can prove this result from mirror formula. From the sign conventions, we have $f>0$ ,$u>0$ and $v$ should be less than zero (for forming real image).
So from mirror formula, $ \frac{1}{v}=\frac{1}{f}-\frac{1}{u} <0$ $\implies u<f$

What you have done is correct. We have to judge the diagram by obtaining the results from the formula but not just simply imagining a diagram. The results suggest that your diagram was wrong and the correct diagram could be the below one:

enter image description here

What you have done is correct. We have to judge the diagram by obtaining the results from the formula but not just simply imagining a diagram. The results suggest that your diagram was wrong and the correct diagram could be the below one:

enter image description here


Extending the comments:
To get a real image the virtual object should lie in between pole and the focus. We can prove this result from mirror formula. From the sign conventions, we have $f>0$ ,$u>0$ and $v$ should be less than zero (for forming real image).
So from mirror formula, $ \frac{1}{v}=\frac{1}{f}-\frac{1}{u} <0$ $\implies u<f$

Source Link
Infinite
  • 277
  • 1
  • 3
  • 15

What you have done is correct. We have to judge the diagram by obtaining the results from the formula but not just simply imagining a diagram. The results suggest that your diagram was wrong and the correct diagram could be the below one:

enter image description here