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Jul 19, 2013 at 15:36 vote accept FraSchelle
Jul 13, 2013 at 7:10 answer added NanoPhys timeline score: 15
Jul 12, 2013 at 15:49 comment added BebopButUnsteady But from another perspective aren't these modes quite different? The local excitation on the surface of a topological insulator are metallic density fluctuations, whereas on a superconductor they are $U(1)$ fluctuations. Simply there is no dissipation on a superconductor, whereas there must be on the topological edge state.
Jul 12, 2013 at 15:29 history edited BebopButUnsteady
Tagged this classy research-level question as research-level
Jul 12, 2013 at 15:28 comment added BebopButUnsteady That is an excellent point about the surfaces of superconductors. Part of the definition of topological insulators is that they are robust against all types of disorder that respect certain discrete symmetries. So maybe one should think about the behavior of trivial superconductor in the presence of random $U(1)$ perturbations.
Jul 12, 2013 at 11:52 history asked FraSchelle CC BY-SA 3.0