Timeline for Is work done by torque due to friction in pure rolling?
Current License: CC BY-SA 4.0
12 events
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| May 24, 2022 at 21:32 | history | edited | John Darby | CC BY-SA 4.0 |
correct typo
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| May 24, 2022 at 20:43 | history | edited | John Darby | CC BY-SA 4.0 |
added 155 characters in body
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| May 24, 2022 at 20:10 | history | edited | John Darby | CC BY-SA 4.0 |
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| May 9, 2022 at 4:01 | comment | added | John Darby | Yes, probably too complicated for no slip. I followed this approach because it made it easier for me to evaluate the case with slip, and to show there is no energy loss with slip from heating due to friction for a rigid body, contrary to what an earlier post stated. | |
| May 9, 2022 at 3:48 | comment | added | Dale | This approach isn’t exactly wrong, but it is (in my opinion) a little unnecessarily complicated. For a wheel rolling without slipping $\vec F \cdot \vec v=0$ which I would just leave as zero. You split it into positive rotational work and negative linear work which cancel out, which seems legitimate. So I think it is ok if you want to do it this way, but I don’t think it is appealing to me personally | |
| May 8, 2022 at 23:59 | history | edited | John Darby | CC BY-SA 4.0 |
added more information in response to lengthy chat discussion
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| May 7, 2022 at 17:03 | comment | added | Alpha Delta | Thank you. I am trying to understand but it is taking some time. I get the relative motion part and am trying to understand the $d\theta= dx/r$ part. | |
| May 7, 2022 at 17:00 | history | edited | John Darby | CC BY-SA 4.0 |
added more information
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| May 7, 2022 at 16:46 | comment | added | John Darby | For rolling without slipping, your comment relates to no instantaneous motion of the point on the surface which is the same as saying $d\theta= dx/r$ in the linked post. But, even with no relative motion friction can do work; consider a mass on a sled and you push the sled, friction from the sled on the mass keeps the mass moving with same acceleration of sled; friction does work to move the mass even there is no relative motion of mass with respect to sled. So I think the above comment is not always true. Friction is complicated and very poorly treated in most physics texts. Does this help? | |
| May 7, 2022 at 16:26 | comment | added | Alpha Delta | Depending on who answers, I have read that the point where friction acts has no instantaneous displacement/no relative motion/moves in a cycloid path which is perpendicular to friction at that point and hence friction can do no work. The linked post does not seem to acknowledge these points. | |
| May 7, 2022 at 16:16 | history | edited | John Darby | CC BY-SA 4.0 |
added more information
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| May 7, 2022 at 16:09 | history | answered | John Darby | CC BY-SA 4.0 |