Timeline for Speed of the Standing Wave in A Pipe
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 15, 2022 at 10:29 | comment | added | Reet Jaiswal | Therefore, for a given pipe or rope, the wavelength of the $n^{th}$ harmonic will never change, since it completely depends on the length itself. If the velocity of the medium changes, the frequency will alter to adjust to the wavelength, and not the other way round. | |
| Apr 15, 2022 at 10:25 | comment | added | Reet Jaiswal | Thus we get nodes and antinodes, nodes being the points which don't move and antinode being the points with maximum displacement. Since the end attached to the vibration generator is necessarily an antinode, and the end attached to the wall is necessarily a node, we can only use specific frequencies in order to generate standing waves that fit this configuration in a consistent repeating pattern. At any other frequency in between we will simply get a chaos of waves. | |
| Apr 15, 2022 at 10:07 | comment | added | Reet Jaiswal | @AliceX You're forgetting that we are talking about standing waves here. I'd suggest you look into how standing waves are formed in the first place, then you'll be able to answer why we can't get standing waves by putting just any frequency in the vibration generator. Standing waves form at integral multiples of a certain frequency. These frequencies(which we call harmonics) are just right to give rise to a situation where waves travelling in one direction interfere with the waves from the opposite direction(these other waves could be reflected off a wall). | |
| Apr 14, 2022 at 16:56 | vote | accept | AliceX | ||
| Apr 14, 2022 at 13:38 | comment | added | AliceX | I disagree with the point that the wavelength depends on the length of the pipe. Let’s change the example to the standing wave on a rope by a vibration generator. I can increase the frequency and it changes the wavelength of the standing wave, so the length of the pipe or rope is not the only factor here. It may stay constant but we can still change the wavelength of the standing wave. What am I getting wrong here? | |
| Apr 14, 2022 at 12:54 | history | edited | Reet Jaiswal | CC BY-SA 4.0 |
deleted 1 character in body
|
| Apr 14, 2022 at 12:47 | history | answered | Reet Jaiswal | CC BY-SA 4.0 |