Timeline for Operator norm of creation and annihilation operators
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Nov 10 at 5:12 | comment | added | Tobias Fünke | Strictly speaking, the bosonic creation and annihilation operators (on the bosonic Fock space) restricted to the subspace consisting of at most $r$ bosons are in fact bounded. What you instead mean, I suppose, is that one should take the sequence $\psi_n:=\otimes^n f/\|f\|^n$ where $f$ is a single-particle vector. Then $\psi_n$ is in the domain of $a(f)$ and $\|a(f)\psi_n\|=\sqrt n \|f\|$, showing that $a(f)$ is unbounded. | |
| Jul 7, 2013 at 9:54 | vote | accept | Stephan Kulla | ||
| Jul 7, 2013 at 9:33 | history | answered | Vibert | CC BY-SA 3.0 |