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Apr 4, 2022 at 21:59 comment added Bill Alsept @Lost You may be interested in the derivation of the individual fringes. See “Single Edge Certainty” at Billalsept.com
Apr 4, 2022 at 13:28 comment added Lost @PhilipWood How does that address the fact that even when the slit was not comparable to the wavelength I was still getting a visible fringe pattern?
Apr 4, 2022 at 12:30 answer added Solomon Slow timeline score: 2
Apr 4, 2022 at 12:03 comment added Philip Wood All you need is in the formula for intensity at angle $\theta$ to the normal for Fraunhofer diffraction at a single slit. It's a standard result.
Apr 4, 2022 at 11:34 history asked Lost CC BY-SA 4.0