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Apr 2, 2022 at 16:45 history edited Cosmas Zachos CC BY-SA 4.0
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Apr 2, 2022 at 16:33 comment added Cosmas Zachos c-numbers are variables which are not operators, so they commute with all operators. There is nothing in your expression failing to commute. (You may also imagine your operator in its diagonal representation, so it is a diagonal array of its c-number eigenvalues.) Your QM course must have covered this...
Apr 2, 2022 at 16:15 comment added LionCereals While I am sure your answer is correct, I don't really understand it. What are "al c-numbers?" Why can commuting operators be treated as vector variables? Is there some literature that I can study on this topic?
Apr 2, 2022 at 15:15 history answered Cosmas Zachos CC BY-SA 4.0