Timeline for How do I take the gradient of the position operator?
Current License: CC BY-SA 4.0
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Apr 2, 2022 at 16:45 | history | edited | Cosmas Zachos | CC BY-SA 4.0 |
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Apr 2, 2022 at 16:33 | comment | added | Cosmas Zachos | c-numbers are variables which are not operators, so they commute with all operators. There is nothing in your expression failing to commute. (You may also imagine your operator in its diagonal representation, so it is a diagonal array of its c-number eigenvalues.) Your QM course must have covered this... | |
Apr 2, 2022 at 16:15 | comment | added | LionCereals | While I am sure your answer is correct, I don't really understand it. What are "al c-numbers?" Why can commuting operators be treated as vector variables? Is there some literature that I can study on this topic? | |
Apr 2, 2022 at 15:15 | history | answered | Cosmas Zachos | CC BY-SA 4.0 |