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Mar 29, 2022 at 19:12 comment added Alex Gower If you could though that would be amazing
Mar 29, 2022 at 17:38 comment added Alex Gower Oh I see, but ultimately this problem is very messy to show easily?
Mar 29, 2022 at 17:36 comment added Qmechanic Well, it becomes a Poisson bracket.
Mar 29, 2022 at 17:35 history edited Qmechanic CC BY-SA 4.0
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Mar 29, 2022 at 17:26 comment added Alex Gower I'm probably being stupid, but wouldn't the commutator evaluate to 0 for classical fields?
Mar 29, 2022 at 17:02 comment added Qmechanic Yes, or its classical counterpart.
Mar 29, 2022 at 16:57 comment added Alex Gower I'm not quite sure how to use this symmetry to get the Noether current. Are you saying that the symmetry is $$\phi(x) \rightarrow \epsilon \int dp \hat a^\dagger_p \hat a_p \phi(x) - \epsilon \phi(x) \int dp \hat a^\dagger_p \hat a_p$$ or something?
Mar 29, 2022 at 16:20 history answered Qmechanic CC BY-SA 4.0