Timeline for Does Heisenberg picture only work for time-dependent Schrödinger equation not Klein-Gordon equation?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 25, 2022 at 17:57 | comment | added | K. Sreeman Reddy | @AlexGower Read about Schrödinger functional they explain how the time-dependent state evolves in Schrödinger picture. I also didn't know about that, found it just now. | |
| Mar 25, 2022 at 17:56 | vote | accept | Alex Gower | ||
| Mar 25, 2022 at 17:54 | comment | added | Tobias Fünke | @AlexGower I guess this is a new question and should be treated separately, no? | |
| Mar 25, 2022 at 17:51 | comment | added | Alex Gower | Thanks, is there any way to solve the Klein Gordon equation in the Schrodinger picture? What would that look like? | |
| Mar 25, 2022 at 17:22 | comment | added | K. Sreeman Reddy | @AlexGower I haven't written it earlier but there is a similar definition for Heisenberg picture states and I added it now. Read Cheng and Li Page number 6. | |
| Mar 25, 2022 at 17:21 | history | edited | K. Sreeman Reddy | CC BY-SA 4.0 |
added 423 characters in body
|
| Mar 25, 2022 at 17:15 | comment | added | Alex Gower | Could you spell out exactly why there isn't an anaologous statement to $|/psi_H\rangle = e^{i H_s t/\hbar} |\psi_S(t)\rangle$ in QFT? Can't we have one for the field configuration states? | |
| Mar 25, 2022 at 17:13 | history | answered | K. Sreeman Reddy | CC BY-SA 4.0 |