Edit in order to address questions in comments:
Anna I am not sure I understand you, but let me try answering. First of all, force is a vector, and Fnet is the vector sum of all forces which on being equal to zero will result in zero acceleration of the object of interest. Now let us simplify things by restricting forces to be in one dimension-you add or subtract depending on whether the force acts along the +x direction or the -x dir ( which dir is positive and which is negative is just a matter of convention). When you say "F-mg" you mean that there are 2 opposing forces on the object of interest, and the resultant will be the net force on the object, and it accelerates (during the interval in which it experiences the force) with a=Fnet/m, where m is the mass of the body/object. Now, if there is only one force acting on the object, the net force will be equal to that force and the object accelerates. I don't see why there should be another force for it to move. But surely, it needs an equal and opposite force if you need the net force on the object to be 0.
Also, I don't know what you mean by force getting "used up". You need an net non zero force on the object to give it an acceleration. Perhaps I can say that the net force is used up in increasing the objects momentum. (if that can make you understand)
When you hit the ball with a golf club:
I don't understand your last sentence where you say the force F should go to zero with time
while hitting, say you hit in a way that the ball moves horizontally on the ground and doesn't leave the ground. That is, you are giving it a horizontal force, and friction does oppose it. If there were no friction or other forces opposite to the direction in which you apply force, the ball while in contact with the golf club would accelerate with a=F/m where F is the force you apply on the ball with mass m. However, since in reality there is friction, acceleration is lesser, it will now be Fnet/m, where Fnet =(F-f) where f is the frictional force.
Gravitational force will not act to accelerate the ball when your force is horizontal: gravity acts in the vertical direction and is balanced by the normal force on the ball by the ground, making the net vertical force=0( as is evident by the fact that the ball doesn't fly into air,leaving the ground). However, if the force F that you apply has a vertical component greater than the gravitational force ,it leaves the ground, and you can then consider the gravitational force in your calculations of the net vertical force.(net force in the vertical direction= vertical component of your force - mg).
Keep in mind that force is a vector quantity and you cannot add horizontal and vertical forces.
Now the ball has an acceleration whose vertical component depends on the net vertical force and the horizontal component depends on the net horizontal force.