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Mar 19, 2022 at 0:00 history tweeted twitter.com/StackPhysics/status/1504970918988328964
Mar 18, 2022 at 23:05 vote accept Rafael Mancini
Mar 18, 2022 at 20:14 answer added Níckolas Alves timeline score: 1
Mar 18, 2022 at 19:51 comment added Níckolas Alves Are you sure of that expression? In my copy, (5.1.26) reads $\epsilon^{ab} = \sum_i \exp(- n \omega_i/a) 2 (\psi_{i I})^{(a}(\psi_{i II})^{b)}$, with a sum, not a product
Mar 18, 2022 at 17:40 comment added Rafael Mancini Yes, that I kind of understand. What I don't understand is that product symbol appearing in the definition of $\varepsilon^{ab}$.
Mar 18, 2022 at 17:25 comment added Gold Wald uses his abstract index notation for Hilbert spaces as well by what I remember, and it can indeed become confusing. Still, these are just tensor products. The quantity $\varepsilon^{ab}$ has two indices because it is an element of a tensor product space. The objects $\psi_{iI}^a$ and $\psi_{iII}^b$ are vectors on the individual factor spaces and $\psi_{iI}^{(a}\psi_{iII}^{b)}$ is (I believe) their symmetrized tensor product.
Mar 18, 2022 at 17:15 history edited Rafael Mancini CC BY-SA 4.0
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Mar 18, 2022 at 16:13 history asked Rafael Mancini CC BY-SA 4.0