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Jun 6 at 11:16 history edited Vincent Thacker CC BY-SA 4.0
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Aug 28, 2023 at 2:21 history edited Qmechanic
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Aug 27, 2023 at 23:47 answer added BowlOfRed timeline score: 0
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Mar 14, 2022 at 7:53 answer added Marko Gulin timeline score: 0
Mar 14, 2022 at 7:24 comment added joseph h @BillWatts Thanks for spotting that Bill. I did read the question very quickly and assumed there was a mass on the end. Cheers.
Mar 14, 2022 at 7:22 comment added Bill Watts @josephh your frequency is for a massless spring with a mass m on the end. That is not what we have here. The only mass is the spring. If only it were that simple.
Mar 14, 2022 at 6:48 comment added joseph h If it was an ideal spring, and you exclude gravity, the spring will continue to oscillate with frequency $\frac{1}{2\pi}\sqrt{\frac{k}{m}}$ But real springs are not ideal. That is why reality differs from theory. And although the force varies with $x$, for each value of $x$, $F_{\text{exerted}}=kx$ In other words, you have to keep increasing the exerted force for increasing values of $x$ and Newton's third law always hold.
Mar 14, 2022 at 6:40 comment added sku A spring wants to be in the relaxed state. If you compress or pull, you are creating a restoring force which is working against you.
Mar 14, 2022 at 6:26 comment added user325381 @sku why does restoring force exist then?When and why is actually it produced in the spring ?
Mar 14, 2022 at 6:19 comment added sku You exert a force on the spring. The spring exerts a force on you. When you let go, the force exerted by spring on you is zero as you would expect. The restoring force still exists and hence the springs goes back.
Mar 14, 2022 at 5:14 history asked user325381 CC BY-SA 4.0